## Errata Sheet for Introduction to Food Engineering (5th edition)

Example 11.1 (pp 653):

step 1: Density = 1/((0.11/1593)+(0.89/998.2)) = 1041 kg /m3

step 2: c = 0.11 x 1041 = 114.5

step 3 = (114.5 x 8314 x 293)/180 = 1550 kPa

## Errata Sheet for Introduction to Food Engineering (4th edition)

By R. Paul Singh and Dennis R. Heldman

Academic Press an imprint of Elsevier Inc.

Errata Sheet

 Item Correction Example 1.1 (p8) In part d, the pressure used in calculation should be 29.38 psia (and not 29.28), the calculated pressure should be 202567 Pa or 202.57 kPa. In alternative calculation, converting 29.38 psia will give 202.58 kPa Page 60, line # 13 a sphere has the smallest surface area-to-volume ratio. Example 2.10 (p105) Step (1) should read P1=P3=Patm Equation 2.145 (p146) On the left hand side, replace uB with u2. Problem 2.8 (p179) pressure drop is 78.86kPa Problem 2.10 (p180) Cf should be 3 Problem 2.13 (p180) mass flow rate = 23 kg/s Example 3.6 (p242) Assume cp of pudding = 4 kJ/kgC Equation 4.85 (p303) In this equation the = and + signs are missing, see equation (4.84) for correct placement of these signs. Example 4.29 (p 376) The relative dielectric constant is 64 Problem 4.52 (p391) Final temperature = 128 C Page 518 (line# 7) Latent heat = 333.3 kJ/kg Example 7.1(p 519) Convective heat transfer coefficient = 50 W/m^2 C Example 12.7 (p677) In step 3, change 2354 to 2365.5, in step 5, change 2.82 to 2.834 in step 7, change 1.276 to 1.282,and in step 9, change 3.077 to 3.08 Table A.2.9 (p786) Eqn for k (thermal conductivity) for Fat: change 2.7604 x 10^-3T to 2.7604 x 10^-4T